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Time period of a particle in SHM depends...

Time period of a particle in SHM depends on the force constant k and mass m of the particle as follows:
`T=2pisqrt(m/k)`.
A simple pendulum executes SHM approximately, why then is the time period of a simple pendulum independent of the mass of the pendulum?

Text Solution

Verified by Experts

In case of simple pendulum, the force constant, `k=(mg)/l`
So, time period, `T=2pisqrt(m/k)=2pisqrt(m/((mg)/l))=2pisqrt(l/g)`
Hence, T is independent of m.
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