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A simple harmonic motion is described by...

A simple harmonic motion is described by a = -16x where a is acceleration and x is the displacement in meter. What is the time period?

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Comparing given equation with `a=-omega^(2)x`, we get `omega^(2)=16`.
Now, `omega=(2pi)/T=sqrt16=4`
Hence the time period,
`T=(2pi)/omega=(2pi)/4=pi/2=3.14/2=1.57s`
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