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A sound wave of frequency 80 Hz gets re...

A sound wave of frequency 80 Hz gets reflected noumally from a large wall. Estimate the distance of the first node and the first antinode from the wall. Given , velocity of sound in air ` = 320 m * s^(-1)` .

Text Solution

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Here, the superposition of the incident and the reflected waves produces a stationary wave. The particles adjacent to the wall cannot vibrate, so a developed at the wall .
Wavelength of the stationary wave , `lambda = (V)/(n) = (320)/(80)= 4 m `
` :.` Distance of the 1 st node from the wall = distance between two consecutive nodes ` = (lambda)/(2) = (4)/(2) = 2 m `
The 1 st antinode ia st the midpoint between these two nodes, so its distance from the wall = 1 m .
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