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Find out the fundamental frequency of a 125 cm long organ pipe closed at one end . Given, velocity of sound in air ` = 350 m*s^(-1)` .

Text Solution

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If the length of the closed pipe is l and the wavelength of the fundamental is `lambda` .
` l = (lambda)/(4) or , lambda = 4 l `
If V is the velocity of sound in air , fundamental frequency, ` n_(0) = (V)/(4l) = (350 xx 100)/(4 xx 125) = 70` Hz .
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