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A 20cm long closed pipe emits a tone of ...

A 20cm long closed pipe emits a tone of frequency 400 Hz . Find out the length of an open pipe emitting a tone of frequency 600 Hz at the same time.

Text Solution

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The fundamental frequency for the closed pipe .
` n_(0) = (V)/(4l) ` [l = length of closed pipe]
The fundamental frequency for the open pipe,
`n_(0)^(.) = (V)/(2L) ` [L = length of open pipe]
` :. (n_(0))/(n_(0)^(.)) = (V) /(4l) *(2L)/(V) = (1)/(2) * (L)/(l)`
or ,` L = 2l* (n_(0))/(n_(0)^(.)) = 2 xx 20 xx (400)/(600) = 26 . 67 ` cm .
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