Home
Class 11
PHYSICS
A tuning fork of frequency 256 Hz is hel...

A tuning fork of frequency 256 Hz is held over the open upper end of a 200 cm long vertical tube filled with water. Then water is allowed to escape gradually through the lower end. Find out the positions of the water surface at the 1st and 2nd resonances. Neglect the end error. The velocity of sound in air = 320 ` m * s^(-1)` .

Text Solution

Verified by Experts

The 1st resonance corresponds to the fundamental tone for the tube closed at one end, if `l_(1)` is the length of the air column at the 1st resonance, then
` n = (V)/(4l_(1))`
or, ` l_(1) = (V)/(4n) = (320 xx 100)/(4 xx 256) = 31 . 25 cm`
The 2nd resonance corresponds to the 1st overtone, which is the 3rd harmonic. if `l_(2)` is the corresponding length of the air column then ,
` n = 3 * (V)/(4l_(2))`
or , ` l_(2) = 3 * (V)/(4n) = 3l_(1) = 3 xx 31 . 25 = 93 . 75` cm
So, the height of the water surface from the bottom of the tube are respectively, (200 - 31 . 25) or 168 . 75 cm and (200 - 93 . 75) or 106 . 25 cm .
Promotional Banner

Topper's Solved these Questions

  • SUPERPOSITION OF WAVES

    CHHAYA PUBLICATION|Exercise Higher order thinking skill (hots) questions|21 Videos

  • SUPERPOSITION OF WAVES

    CHHAYA PUBLICATION|Exercise Multiple choice questions (Based on standing wave)|5 Videos

  • STATICS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|3 Videos

  • THERMOMETRY

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIEVE - WBJEE|1 Videos

Similar Questions

Explore conceptually related problems

A tuning fork of frequency 256 Hz is held over the open upper end of a 200 cm long vertical pipe filled with water and the water is slowly darined out through the bottom end of the pipe. Determine the positions of the water level at the time of the first and the second resonances. Neglect the end error. Velocity of sound in air = 320 m* s^(-1) .

Find out the frequency of the first overtone emitted by a 1 . 25 m long organ pipe closed at one end. Given , velocity of sound in air = 320 m * s^(-1)

Find out the fundamental frequency of a 125 cm long organ pipe closed at one end . Given, velocity of sound in air = 350 m*s^(-1) .

The length of an organ pipe closed at one end is 90 cm . Find out the frequency of the harmonic next to the fundamental . Velocity of sound in air = 300 m* s^(-1) .

Determine the frequencies of first three overtones produced in a 50 cm long pipe open at both ends . [Velocity of sound in air = 330 m*s^(-1) ]

The fundamental frequency of a 100 cm long sonometer wire is 330 Hz. Find out the velocity of transverse wave in the wire and the wavelength of the resulting sound waves in air . Given , velocity of sound in air = 330 m * s ^(-1) .

A vibrating tuning fork of frequency 340 Hz is held over a cylindrical pipe. The length of the pipe is 120 cm . Now water is slowly poured into it. What should be the water level at which resonance will occur ? Velociy of sound in air = 340 m*s^(-1) .