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A diver sends an audio signal from some ...

A diver sends an audio signal from some depth under water. This signal produces 5 beats per second with the note emitted by a 20 cm long pipe whose one end is closed. Find out the frequency and the wavelength of the audio signal inside water. Given , velocity of sound in air ` = 360 m * s^(-1) ` and that in water ` = 1500 m * s^(-1)` .

Text Solution

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Fundamental frequency of the 20 cm long pipe closed at one end . ,br. `n_(0) = (V) / (4l) = (360)/(4 xx (20 xx 0 . 0 1)) = 450` Hz
As 5 beats are produced per second, the frequency of the audio signal is either, (450 - 5) = 445 Hz or (450 + 5 ) = 455 Hz .
The frequency does not change due to refraction from water to air . So the wavelength inside water is
either `(1500)/(445) = 3.37 m ` or, `(1500)/(455) = 3 . 30 ` m .
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