The superposltion of two progresslve waves produce a stationary wave represented as y = a cos (0 . 0 1 x) sin (100 t) m . What is the velocity of the two component waves ?

Answer

Two progressive waves represented as ` y_(1) = A sin (omega t - kx) and y_(2) = A sin (omega t + kx) ` superpose to form a stationary wave ` y = y_(1) + y_(2) = 2A cos kx sin omega t ` .
Comparing the given eqution with this standard form, we have k = 0 . 01 ` m^(-1) and omega = 100` Hz . So the wave velocity ,
`V = (omega)/(k) = (100)/(0 . 01) = 10^(4) m * s^(-1)` .