Home
Class 11
PHYSICS
Discuss the result of superposition of t...

Discuss the result of superposition of two waves `y_(1) = A"sin" (2pi)/(lambda_(1)) (Vt - x) and y_(2) = A "sin" (2pi)/(lambda_(2)) (Vt-x) `
[here `lambda_(1)` is slightly greater than ` lambda_(2)` ] .

Promotional Banner

Topper's Solved these Questions

  • SUPERPOSITION OF WAVES

    CHHAYA PUBLICATION|Exercise Problem Set -I (Based on Standing Wave)|1 Videos

  • SUPERPOSITION OF WAVES

    CHHAYA PUBLICATION|Exercise Problem Set -I (Based on Transverse Vibration of String and Sonometer)|14 Videos

  • SUPERPOSITION OF WAVES

    CHHAYA PUBLICATION|Exercise Shoet Answer type question - I|9 Videos

  • STATICS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|3 Videos

  • THERMOMETRY

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIEVE - WBJEE|1 Videos

Similar Questions

Explore conceptually related problems

An incident wave and a reflected wave are represented by xi _(1) = a "sin" (2pi)/(lambda) (vt - x) and xi _(2) = a "sin"(2pi)/(lambda) (vt + x) Derive the equation of the stationary wave and calcu-late the position of the nodes and antinodes.

The unit of both x and y is m in the expression y=A sin[(2pi)/(lambda)(ct-x)]. Then

When two progressive waves y_(1) = 4 sin (2 x - 6t) and y_(2) = 3 sin (2x - 6t -(pi)/(2)) are superposed, the amplitude of the resultant wave is

In the equation Y = A sin2pi/lambda (ct - x) The unit of X is same with which quantity?

If int (dx)/(1+sinx) = tan (x/2 - pi/lambda) + b , then the value of lambda is -

The equations of two sound waves are given gelow : y_(1) = 10 "sin" (pi)/(150) (33000 t - x ) cm and y_(2) = 10 "sin" (pi)/(165) (33000 t - x) cm How many beats will be produced per second due to superposition of these two waves ?

Two waves are expressed as, y_(1) = a sin omega_(1) ((x)/(c)-t) and y_(2) = a sin omega_(2) ((x)/(c)-t) Find the resultant displacement due to superposi-tion of the two waves .