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If the tension and diameter of a sonomet...

If the tension and diameter of a sonometer wire of fun-damental frequency n are doubled and the density halved, then its fundamental frequency will become

A

`(n)/(4)`

B

`sqrt(2)` n

C

n

D

`(n)/(sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
C

Mass per unit length of a wire ` m = pi r^(2) rho `
[r = radius, `rho` density of the material]
` :.` fundamental frequency , n ` = (1)/(2l) sqrt((T)/(m)) = (1)/(2l) sqrt((T)/(pi rho))`
`:.` In this case, ofter changing tension and density of sonometer wire, the frequency is
`n^(.) = (1)/(2l(2pi)) sqrt((2T)/(pi((rho)/(2))))=(1)/(4lr) sqrt((4T)/(pi rho))`
` = (1)/(2lr)sqrt((T)/(pi rho)) = n`
[ iIf diameter is doubled radius is also doubled]
`:.` Fundamental frequency remains the same.
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