Two tuning forks vibrating simultaneously produce 5 beats per second. Frequency of one fork is 275 Hz . A small wax is attached to the other fork and 2 beats per second are produced when the two vibrate simultaneously. Find the frequency of the other fork.

Explanation

Let the frequency of the other fork bex .
beat frequency = difference in the frequencies of the two tuning forks .
If `xlt 275` Hz . Before waxing we have , `275 - x = 5 or xx = 270 ` Hz . After waxing, x will decrease , so the beat frequency will increase.
`:. x gt 275 ` Hz , and before waxing we have, `x - 275 = 5 or x = 280 ` Hz . After waxing x will decrease slightly, so the beat frequency will decrease to 2 .