If the abscissa and ordinates of two points `Pa n dQ` are the roots of the equations `x^2+2a x-b^2=0` and `x^2+2p x-q^2=0` , respectively, then find the equation of the circle with `P Q` as diameter.

If the abscissa and ordinates of two points P and Q are the roots of the equations x^(2)+2ax-b^(2)=0 and x^(2)+2px-q^(2)=0 respectively,then find the equation of the circle with PQ as diameter.

The abscissae and ordinates of the points A and B are the roots of the equations x^(2)+2ax+b=0 and x^(2)+2cx+d=0 respectively,then the equation of circle with AB as diameter is

Abscissas and ordinates of points A and B are roots of equation x^(2) + 2ax - b^(2) = 0 " and " y^(2) + 2py - q^(2) = 0 respectively. Equation of circle with AB as a diameter is

The abscissae of two points A and B are the roots of the equaiton x^2 + 2x-a^2 =0 and the ordinats are the roots of the equaiton y^2 + 4y-b^2 =0 . Find the equation of the circle with AB as its diameter. Also find the coordinates of the centre and the length of the radius of the circle.

A abscissa of A and B are the roots of the equation x^2+2ax-b^2=0 and their ordinates are roots of the equation y^2+2py-q^2=0 . The equation of the circle with AB as diameter is