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सारणिक द्वारा हल कीजिये : 3x-4y=1...

सारणिक द्वारा हल कीजिये : `3x-4y=1,2x-7y=3`

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3x-4y=-7,5x-2y=0

3x-y=7; 2x+4y=0

3x+2y=14; x+4y=7

Solve the following by Cramer's rule : 3x-4y=1, 2x-7y=3

solve for x and y - 2x+3y=7 3x-4y=2

2x + 3y-5z = 7, x + y + z = 6,3x-4y + 2z = 1, then x =

Solve : 3x+ 2y = 14 - x+ 4y = 7

{:(3x + 2y = 4),(2x - 3y = 7):}

{:(3x + 2y = 4),(2x - 3y = 7):}

3x-4y+2z=-1 2x+3y+5z=7 x+z=2