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In a DeltaABC,(a+b+c)(b+c-a)=lambdabc, t...

In a `DeltaABC,(a+b+c)(b+c-a)=lambdabc`, then

A

`lambda lt -6`

B

`lambda gt 6`

C

`0 lt lambda lt 4`

D

`lambda gt 4`

Text Solution

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The correct Answer is:
C
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