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In a triangle ABC, C=90^@. Then (a^2-b^2...

In a triangle ABC, `C=90^@`. Then `(a^2-b^2)/(a^2+b^2)`=

A

`sin(A+B)`

B

`sin(A-B)`

C

`cos(A+B)`

D

`cos(A-B)`

Text Solution

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The correct Answer is:
B
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