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In a DeltaABC,(a+b+c)(tan""A/2+tan""B/2)...

In a `DeltaABC,(a+b+c)(tan""A/2+tan""B/2)=`

A

`2c cot(C )/(2)`

B

`2a cot (A)/(2)`

C

`2b cot (B)/(2)`

D

`tan(C )/(2)`

Text Solution

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The correct Answer is:
A
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