" 29."int_(0)^( pi)(dx)/((6-cos x))

int_(0)^( pi)(dx)/(1+cos x)

int_(0)^(pi/2)(1)/(6-cos x)dx

int_0^(pi) (dx)/(a+b cos x) =

Compute the integrals : (a) int_(0)^(pi//2) (cos x dx)/( 6 - 5 sin x + sin^(2) x) (b) int _(0)^(pi//2) (dx)/( 2 + cos x)

I=int_(0)^(2 pi)cos^(-1)(cos x)dx

int_(0)^( pi)[cos x]dx

int_(0)^( pi)|cos x|dx

int_(0)^( pi)|cos x|dx

If A=int_(0)^( pi)(cos x)/((x+2)^(2))dx, then int_(0)^( pi/2)(sin2x)/(x+1)dx is equal to

int_(0)^((pi)/(2))(x)/(sin x+cos x)dx