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tanh^(-1) (1/2)= 1/2 loge 3 అని చూపండి....

`tanh^(-1) (1/2)= 1/2 log_e 3` అని చూపండి.

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2tanh^(-1)((1)/(2))=

S.T Tanh^(-1) 1/2 = 1/2 log_(e)3 .

2 "Tanh"^(-1) 1/2 =

"Tanh"^(-1)((1)/(3))=

"Tanh"^(-1) (1//2) + "Coth"^(-1) (2) =

If A = "Tanh"^(-1) (1//2) + "Coth"^(-1) (2), "B = sinh "("Cosh"^(-1)9) . "C = sech"^(2) ("Tanh"^(-1) 1//2)+ "cosech"^2 ("Coth"^(-1) 3) then