When the origin is shifted to the point (2 , 3) the transformed equation of a curve is `x^(2) + 3xy - 2y^(2) + 17 x - 7y - 11 = 0 ` . Find the original equation of curve.
Text Solution
Verified by Experts
The correct Answer is:
`x^2+3xy-2y^2+4x-y-20=0`.
Topper's Solved these Questions
TRANSFORMATION OF AXES
SRISIRI PUBLICATION|Exercise 2 D (SAQ)|2 Videos
THREE DIMENSIONAL CO-ORDINATES
SRISIRI PUBLICATION|Exercise SPQ|3 Videos
TRIGONOMETRIC EQUATIONS
SRISIRI PUBLICATION|Exercise SPQ|8 Videos
Similar Questions
Explore conceptually related problems
If the transformed equation of curve is 3x^(2) + xy - y^(2) - 7x + y + 7 = 0 when the axes are translated to the point (1,2) then the original equation of curve is
If the transformed equation of a curve is X^(2) + Y^(2) = 4 when the axes are translated to the point (3, -4) then find the original equation of the curve.
If the transformed equation of a curve is 17x^(2) - 16xy + 17y^(2)=225 when the axes are rotated through an angle 45^(@) , then the original equation of the curve is
SRISIRI PUBLICATION-TRANSFORMATION OF AXES-2 D (SAQ)