Find the transformed equation of `x^(2)+2sqrt3 xy-y^(2) = 2a^(2)` when the axes are rotated through an angle `30^(0).`
Text Solution
Verified by Experts
The correct Answer is:
`X^2-Y^2=a^2`.
Topper's Solved these Questions
TRANSFORMATION OF AXES
SRISIRI PUBLICATION|Exercise 2 D (SAQ)|2 Videos
THREE DIMENSIONAL CO-ORDINATES
SRISIRI PUBLICATION|Exercise SPQ|3 Videos
TRIGONOMETRIC EQUATIONS
SRISIRI PUBLICATION|Exercise SPQ|8 Videos
Similar Questions
Explore conceptually related problems
Find the transformed equation of x^(2) + 2 sqrt(3) xy - y^(2) = 2a^(2) when the axes are rotated through an angle 30^(0)
The transformed equation of x^(2) - 2sqrt(3)xy -y^(2) =2a^(2) when the axes are rotated through an angle 60^(@) is
The transformed equation of x^(2) + y^(2) =a^(2) when the axes are rotated through an angle 18^(@) is
Find the transformed equation of 3x^(2) + 10xy + 3y^(2) = 9 when the axes are rotated through an angle (pi)/(4)
The transformed equation of x^(2) + y^(2) =r^(2) when the axes are rotated through an angle 36^(@) is
Find the transformed equation of 4xy-3x^(2) = a^(2) when the axes are rotated through an angle Tan^(-1) 2.
The transformed equation of x^(2)//a^(2) -y^(2)//b^(2)=1 when the axes are rotated through an angle 90^(@) is
If the transferred equation of a curve is x^(2) + 2sqrt(3)xy - y^(2) = 2a^(2) when the axes are rotated through an angle 60^(@) , then the original equation of the curve is
SRISIRI PUBLICATION-TRANSFORMATION OF AXES-2 D (SAQ)