A particle is moving along a line according `s=f(t)=4t^3-3t^2+5t-1` where s is measured in meters and t is measured in seconds. Find the velocity and acceleration at time t. At what time the acceleration is zero.

A particle is moving along a line according to s=f(t) =4t^(3)-3t^(2)+5t-1 where s is measured in meter and t is measured in seconds. Find the velocity and acceleration at time t. At what time the acceleration is zero.

A particle is moving along a line according s= f(t) = 8t + t^3 . Find the initial velocity

A particle is moving along a line according s= f(t) = 8t + t^3 . Find acceleration at t = 2 sec.

A particle is moving along a line according to the law s=t^3-3t^2+5 . The acceleration of the particle at the instant where the velocity is zero is

A particle moves along a line according to the law s=t^4-5t^2+8 . The intial velocity is

A particle moving along a straight line has the relation s=t^(3)+2t+3 , connecting the distance s describe by the particle in time t. Find the velocity and acceleration of the particle at t=4 sec.

A particle moving along a straight line has the relation s =t^2 +3, connecting the distance s described by the particle in time 1. Find the velocity and acceleration of the particle at t=4 seconds.

A particle moves along a line by s = t^(3) - 9t^(2) + 24t . Then S is decreasing when t in