A : The image of the origin with respect to the line `x+y+1=0` is (-1, -1)
R : If (h, k) is the image of `(x_(1), y_(1))` with respect to the line `ax+by+c=0` then `(h-x_(1))/(a)=(h-k_(1))/(b)=(-2(ax_(1)+by_(1)+c))/(a^(2)+b^(2))`

A : The foot of the perpendicular from (3, 4) on the line 3x-4y+5=0 is (81//25, 92//25) R : If (h, k) is the foot of the perpendicular from (x_(1), y_(1)) to the line ax+by+c=0 then (h-x_(1))/(a)=(h-k_(1))/(b)=(-(ax_(1)+by_(1)+c))/(a^(2)+b^(2))

If Q(h,k) is the foot of the perpendicular of P(x_(1),y_(1)) on the line ax+by+c=0 then prove that (h-x_(1)),a=(k-y_(1)),b=-(ax_(1)+by_(1)+c):(a^(2)+b^(2)) .

The distance from the orgin to the image of (1,1) with respect to the line x+y+5=0 is

Find the image of the line x-y-1=0 in the line 2x-3y+1=0 .