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A(5,3) and B(3,-2) are 2 fixed points. F...

A(5,3) and B(3,-2) are 2 fixed points. Find the equation of locus of P, so that the area of `trianglePAB` is 9sq. Units.

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A (5,3) & (3,-2) are 2 fixed points . Find the equation of locus of P , so that the area of triangle PAB is 9 sq .units .

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Knowledge Check

  • A(2, 3), B(2, -3) are two points. The equation to the locus of P such that PA+PB=8 is

    A
    `16x^(2)+7y^(2)-64x-48=0`
    B
    `16x^(2)+7y^(2)-64x+48=0`
    C
    `16x^(2)-7y^(2)+64x-48=0`
    D
    `16x^(2)-7y^(2)+64x+48=0`
  • A (2, 3 ) , B ( 2, - 3 ) are two points. The equation to the locus of P such that PA + PB = 8 is

    A
    ` 16 x ^ 2 + 7y ^ 2 - 64 x - 48 = 0 `
    B
    ` 16x ^ 2 + 7y ^ 2 - 64 x + 48 = 0 `
    C
    ` 16 x ^ 2 - 7y ^ 2 + 64 x - 48 = 0`
    D
    ` 16 x ^ 2 - 7y ^2 + 64 x + 48 = 0`
  • A(1, 1), B(2, 3), C(-1, 1) are the points. If P is a point such that the area of the quadrilateral PABC is 3 sq. units, then the locus of P is

    A
    `y^(2)+6y=0`
    B
    `y^(2)-6y=0`
    C
    `x^(2)+6x=0`
    D
    `x^(2)-6x=x`
  • Similar Questions

    Explore conceptually related problems

    A(5, 3) and B (3, -2) are two fixed points. Find the equation of the locus of P so that the area of triangle PAB is 9.

    A(2, 3) and B(-3, 4) are two given points. Find the equation of locus of P so that the area of the triangle PAB is 8.5.

    A(2,3) and B(-3,4) be two given points. Find the equation of the locus of P so that the area of the triangle PAB is 8.5 sq.units.

    A (2,3) and (-3,4) be two given points . Find the equation of the locus of P so that the area of the triangle PAB is 8.5 sq.units .

    Find the equation of locus of a point, the sum of whose distances from (0,2),(0,-2) is 6unit.