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Find the equation of locus of P, if the ...

Find the equation of locus of P, if the line segment joining (2,3) & (-1,5) subtends a right angle at P.

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Knowledge Check

  • The equation to the locus of P such that the join of (a, b) and (b, a) subtend a right angle at P, is

    A
    `x^(2)+y^(2)-ax-by+ab=0`
    B
    `x^(2)+y^(2)-ax-by+2ab=0`
    C
    `x^(2)+y^(2)-(a+b)(x+y)+ab=0`
    D
    `x^(2)+y^(2)-(a+b)(x+y)+2ab=0`

  • The locus of the point if the join of the points (-4,2,3) ,(2,-1,5) subtends a right angle at P is

    A
    `x^2+y^2-z^2+2x-y-8z+5=0`
    B
    `x^2+y^2-z^2+2x-y-8z-5=0`
    C
    `x^2+y^2+z^2+2x-y-8z+5=0`
    D
    `x^2-y^2-z^2-2x-y-8z-5=0`

  • The midpoint of the line segment joining (2,3,-1 ), (4,5,3,) is

    A
    (3,4,1)
    B
    (4,1,3)
    C
    (3,-4,-1)
    D
    (-4,1,3)

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    Find the locus of a point P If the join of the points (2,3) and (-1,5) subtends a right angle at P.

    Find the mid point of the line segment joining (3,6) and (5,-2).

    Find the equation of the plane bisecting the line segment joining (2,0,6) and (-6,2,4) and perpendicular to it.

    The equation of the perpendicular bisector of the line segment joining (1,2),(3,4)is

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