A parallel plate capacitor has the space between its plates filled by two slabs of thickness `(d)/(2)` each and dielectric constant `K_(1)` and `K_2`. d is the plate separation of the capacitor. The capacitance of the capacitor is

You are given an air filled parallel plate capacitor c_(1) . The space between its plates is now filled with slabs of dielectric constant k_(1) and k_(2) as shown in c_(2) . Find the capacitances of the capacitor c_(2) if area of the plates is A distance between the plates is d.

A parallel plate capacitor has plate area A and plate separation d. The space betwwen the plates is filled up to a thickness x (ltd) with a dielectric constant K. Calculate the capacitance of the system.

A parallel plate capacitor of plate area A and separation d is filled with two materials each of thickness d/2 and dielectric constants in_1 and in_2 respectively. The equivalent capacitance will be

The capacitance of a parallel plate capacitor with plate area A and separation d is C . The space between the plates in filled with two wedges of dielectric constants K_(1) and K_(2) respectively. Find the capacitance of resulting capacitor.

A parallel-plate capacitor with plate area A has separation d between the plates. Two dielectric slabs of dielectric constant K_1 and K_2 of same area A//2 and thickness d//2 are inserted in the space between the plates. The capacitance of the capacitor will be given by :

A parallel plate capacitor with vacuum between its plates has capacitance C . A slabe of dielectric constant K and having the same thickness as the separation between the plates is introduced so as to fill 1//3^(rd) of the capacitor as shown in the figure. the new capacitance will be

If a dielectric slab of thickness 5 mm and dielectric constant K=6 is introduced between the plates of a parallel plate air capacitor, with plate separation of 8 mm, then its capacitance is

A parallel plate capacitor with oil as a dielectric between the plates has a capacitance C. if the oil, with dielectric constannt (K=3), is removed, then the capacitance of the capacitor will be