`int(1)/(2)(3-2x)dx`

int_(1)^(2)(3x-2)dx

Evaluate: int(1)/(2-3cos2x)dx

Evaluate: int(1)/(2-3cos2x)dx

int(1)/(x^(2)-2x-3)dx=

int(x+1)^2(2x+3)dx

Evaluate int_(1)^(2)(3x^2+1)dx

int_(1)^(2)(3x)/(9x^(2)-1)dx

Evaluate: int(1)/(sqrt(3-2x-x^(2)))dx

(1) int_(1)^(2)(2x^(3))dx

The area of the region for which is int_(1)^(3)(3-2x-x^(2))dx(b)int_(0)^(3)(3-2x-x^(2))dx int_(0)^(1)(3-2x-x^(2))dx (d) int_(-1)^(3)(3-2x-x^(2))dx*00