If `|x+3|geq10 ,` then `x in (-13 ,\ 7]` b. `x in (-oo,-13)uu(7,oo)` c. `x in (-13 ,7)` d. `x in (-oo,\ -13]uu[7,oo)`

If |x+3|>=10, then x in(-13,7] b.x in(-oo,-13)uu(7,oo) c.x in(-13,7) d.x in(-oo,-13]uu[7,oo)

If |x+2|lt=9 then x in (-7, 11) b. x in [-11 ,7] c. x in (-oo,7)uu(11 ,oo) d. x in (-oo,-7)uu[11 ,oo)

If |x+2|lt=9 then x in (-7, 11) b. x in [-11 ,7] c. x in (-oo,7)uu(11 ,oo) d. x in (-oo,-7)uu[11 ,oo)

If -3x+17<-13 ,\ t h e n x in (10 ,oo) b. x in [10 ,oo) c. x in (-oo,\ 10] d. x in [-10 , 10)

If |x-1|>5, then a. x in (-4,6) b. x in [-4,6] c. x in (-oo,-4)uu(6,oo) d. x in (-oo,-4)uu[6,oo)

If |x-1|>5, then x in(-4,6) b.x in[-4,6] c.x in(-oo,-4)uu(6,oo) d.x in(-oo,-4)uu[6,oo)

If x and a are real numbers such that a>0 and |x|>a, then x in(-a,oo) b.x in[-oo,a) c.x in(-a,a) d.x in(-oo,-a)uu(a,oo)

If -3x+17<-13, then x in(10,oo)bx in[10,oo)c.x in(-oo oo,10]d .x in[-10,10)

Complete solution set of the inequation (x^2-1)(x^2-6x+8)geq0 is (a) x in [-1,1]uu[2,4] (b) x in (-oo,-1)uu[1,2]uu[4,oo] (c) x in [-1,2]uu[4,oo] (d) none of these

For x^2-(a+3)|x|=4=0 to have real solutions, the range of a is a (-oo,-7]uu[1,oo) b (-3,oo) c (-oo,-7] d [1,oo)