Prove that: (i) `tan 8x-tan6x-tan2x=tan8x tan6x tan2x`

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tan x+tan2x=tan3x

tan3x-tan2x-tan x=tan3x tan2x tan x

tan 5x tan3x tan2x=

tan5x.tan3x*tan2x =

tan x+tan2x+tan3x=0

tan8x-tan5x-tan3x=m tan8x tan5x tan3x then m

Prove that tan2x=(2tanx)/(1-tan^2 x)

tanx + tan2x + tan3x = tanx tan2x tan3x

Show that : tan 3x tan 2x tan x =tan 3x-tan2x-tanx