If `A ,\ B ,\ C ,\ D` be the angles of a cyclic quadrilateral, taken in order, prove that: `cos(180^0-A)+cos(180^0+B)+cos(180^0+C)-sin(90^0+D)=0`

If A, B, C and D be the angles of a cyclic quadrilateral, taken in order, prove that : cos (180^@- A) + cos (180^@+ B) + cos (180^@+ C)- sin (90^@ + D) = 0 .

If A,B,C,D be the angles of a cyclic quadrilateral,taken in order, prove that: cos(180^(@)-A)+cos(180^(@)+B)+cos(180^(@)+C)-sin(90^(@)+D)=0

If A, B, C, D be the angles of a cyclic quadrilateral, taken in order, prove that : cos A + cos B + cos C+ cos D = 0 .

If A ,\ B ,\ C ,\ D are angles of a cyclic quadrilateral, prove that cos A+cos B+cos C+cos D=0.

If A ,B ,C ,D are angles of a cyclic quadrilateral, then prove that cos A+cos B+cos C+cos D=0

If A ,B ,C ,D are angles of a cyclic quadrilateral, then prove that cos A+cos B+cos C+cos D=0

If A ,B ,C ,D are angles of a cyclic quadrilateral, then prove that cos A+cos B+cos C+cos D=0

If A, B, C, D are the four angle taken in order of a cyclic quadrilateral, prove that (ii) cos (180^(@) - A) + cos (180^(@) + B) + cos (180^(@) + C) - sin (90^(@) + D) = 0

If ABCD is a cyclic quadrilateral then co (180^(@) +A) + cos (180^(@) - B) +cos(180^(@)-C) - sin (90^(@) - D)=

If A,B,C and D are the angles of cyclic quadrilateral, prove that: i) cosA + cosB+cosC+cosD ii) cos(180^(@)-A)+cos(180^(@)+B)+cos(180^(@)+C)-sin(90^(@))