One proton beam enters a magnetic field of `10^(-4) T` normally. Specific charge `=10^(11)C//kg`. Velocity `=10^(7)m//s`. What is the radius of the circle described by it

A proton beam enters magnetic field of 10^(-4) "Wb//m^(2) normally. If the specific charge of the proton is 10^(11) C//kg and its velocity is 10^(9)m//s then the radius of the circle described will be

A proton beam enters magnetic field of 10^(-4) "Wb//m^(2) normally. If the specific charge of the proton is 10^(11) C//kg and its velocity is 10^(9)m//s then the radius of the circle described will be

A proton beam enters a magnetic field of 10^(-4)Wb m^(-2) normally. If the specific charge of the proton is 10^11 C kg^(-1) and its velocity is 10^9 ms^-1 ,then the radius of the circle described will be:

A beam of ions with velocity 2xx 10^(5) m/s enters normally into a uniform magnetic field of 4 xx 10^(-2) T. if the specific charge to the ions is 5xx 10^(7) C/kg, the radius of the circular path described will be

A beam of ions with velocity 2xx 10^(5) m/s enters normally into a uniform magnetic field of 4 xx 10^(-2) T. if the specific charge to the ions is 5xx 10^(7) C/kg, the radius of the circular path described will be

A monoenergetic electron beam with electron speed of 5.20 xx10^(6) "m s"^(-1) is subject to a magnetic field of 1.30 xx 10^(-4) T normal to the beam velocity . What is the radius of the circle traced by the beam , given e/m for electron equals 1.76 xx10^(11) " C kg"^(-1)

A monoenergetic electron beam with electron speed of 5.20xx10^(6) ms^(-1) is subject to a magnetic field of 1.30xx10^(-4)T normal to the beam velocity. What is the radius of the circle traced by the beam? Given e//m = 1.76 xx 10^(11) kg^(-1) .

A proton beam enters a magnetic field of 10^(-4) " Wb " m^(-2) Wb normally. If the specific charge of the proton is 10^(11) " C " kg^(-1) and its velocity is 10^(9) " m "s^(-1) then the radius of the circle described will be