Sum of square of `m` natural numbers

Sum of square of n natural number

Find the sum of squares of first 9 natural numbers

The difference between the sum of squares of first n natural numbers and the sum of first n natural numbers is always divisible by 2.

If m is the square of a natural number n, then n is

If the difference of the squares of two natural numbers is 19. Find the sum of the square of these numbers? (a) 189 (b) 190 (c) 181 (d) None of these

If (2^(200)-2^(192).31+2^n) is the perfect square of a natural number , then find the sum of digits of 'n' .

The sum of the squares of first 50 natural numbers is :