Point (-10,0) lies

The point (-1,0) lies on the circle x^2+y^2-4x+ 8y + k=0 . The radius of the circle is

The point P(-1,0) lies on the circle x^(2)+y^(2)-4x+8y+k=0 . Find the radius of the circle Also determine the equation of the circle of equal radius which touches the given circle at P.

Point (-7, 0) lies

Point (0,0) lies on both axes .

The point (0,0) lies on the

Point (0, -8) lies

The point (-4,0,7) lies on the

Point (0,2) lies on x - axis .

Point (-3,5) lies in the