In an experiment, 200V AC is applied at the end of an LCR circuit. The circuit consists of an inductive reactance
`(X_(L))` =`50Omega`, capacitive reactance
`(X_(c)L=50Omega`, and capacitives resistance
`(R ) = 10Omega`, The impendance of the circuit is

In an experiment, 200V AC is applied at the end of an LCR circuit. The circuit consists of an inductive reactance (X_(L)) = 50Omega , capacitive reactance (X_(c))=50Omega , and capacitives resistance (R ) = 10Omega , The impendance of the circuit is

200V A.C. is applied at the ends of an LCR circuit. The circuit consists of an inductive reactance X_(L) = 50Omega capacitive reactance X_(c) = 50 Ω and ohmic resistance R = 10 Ω . Calculate the impedance of the circuit and also potential differences across L and R What will be the potential difference across L-C

200V A.C. is applied at the ends of an LCR circuit. The circuit consists of an inductive reactance X_(L) = 50Omega capacitive reactance X_(c) = 50 Ω and ohmic resistance R = 10 Ω . Calculate the impedance of the circuit and also potential differences across L and R What will be the potential difference across L-C

A 200V ac source is applied in a LCR series circuit which consists of an inductive reactance of 50Omega a capacitive reactance of 50Omega and the resistance of 10 Omega The potential difference across the resistance is .

In a seris LCR circuit, the inductive reactance (X_(L)) is 10 Omega and the capacitive reactance (X_(C)) is 4 Omega . The resistance (R) in the circuit is 6 Omega. The power factor of the circuit is :

An a.c. circuit an inductive reactance of 80Omega and a pure resistace of 60 Omega . What is the impendance of the circuit?

In L-R circuit, resistance is 8Omega and inductive reactance is 6Omega then impedance is:

In L-R circuit, resistance is 8Omega and inductive reactance is 6Omega then impedance is:

In an LCR circuit, inductive reactance and capacitive reactance was found to be equal. The resistance was found to be 20Omega . The probable impedance of the combination is