" (iii) "sec^(-1)(tan2x)

sec^(2)2x=1-tan2x

sec^(2)2x=1-tan2x

Solve the following trigonometric equations, (i) sec^(2)2x=1-"tan"2x

Lim_(x to pi) (1+sec^(3)x)/(tan^(2)x)

If (x)=sec^(-1)(sin(2tan^(-1)(x)))+cos ec^(-1)(cos(2tan^(-1)(x)))f(x)=sec^(-1)(sin(2tan^(-1)(x)))+cos ec^(-1)(cos(2tan^(-1)(x))) has m values in its domain and n values inthe range,then (m+n) is (A)4(B)5(C)6(D) none

int (tanx sec^(2)x)/((1-tan^(2)x))dx.

Evaluate: int(sec^2x)/(1-tan^2x)\ dx

Evaluate: int(sec^(2)x)/(1-tan^(2)x)dx

int(sec^(2)x)/(1-tan^(2)x)dx

Evaluate: int(sec^2x)/(1-tan^2x)\ dx