" If "s_(n)=n^(2)p" and "s_(m)=m^(2)p_(1)m!=n" in A.P.,then "s_(p)" is "

S_n in A.P.=

If in an A.P.S_(n)=n^(2)p and S_(m)=m^(2)p, then S_(p) is equal to

If S_(m)=m^(2) p and S_(n)=n^(2)p , where m ne n in an AP then prove that S_(p) =P^(3)

If in an A.P.S_(n)=n^(2)q and S_(m)=m^(2)q, where S_(r) denotes the sum of r terms of the A.P.then S_(q) equals (q^(3))/(2) b.mnq c.q^(3) d.(m^(2)+n^(2))q

If in an A.P. S_(n) = qn^(2) and S_(m) = qm^(2) , where S_(r ) denotes the sum of r terms of the A.P. , then S_(q) equals :

If in an A.P, S_n=n^2p and S_m=m^2p , then S_p is equal to

The sum of first n terms of an A.P. is S_n .If S_n=n^2p and S_m=m^2p(mnen) .Show that S_p=p^3 .

If in an A.P, S_n=n^2p and S_m=m^2p , then prove that S_p is equal to p^3

(m+n)P_(2)=56,^(m-n)P_(2)=30 then