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In the figure AC||BD , prove that: (i)...

In the figure AC||BD , prove that:
`(i) triangleACE ~ triangleBDE (ii) (AE)/(CE)= (BE)/(DE)`

Text Solution

Verified by Experts

(i) AC||BD
`{:(angle1=angle2),(angle3=angle4):}}` ( alternate angles)
( by AA criterion)
(ii) Now , since `triangleACE~ triangleBDE`
`(AE)/(BE) = (CE)/(DE)` (corresponding sides of similar `triangles` are proportional)
`Rightarrow (AE)/(CE) = (BE)/(DE)` ( by alternendo)
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