Home
Class 10
MATHS
Nazinia is fly fishing in a stream. T...

Nazinia is fly fishing in a stream. The tip of her fishing rod is 1.8 m above the surface of the water and the fly at the end of the string rests on the water 3.6 m away and 2.4 m from a point directly under the tip of the rod. Assuming that h

Text Solution

Verified by Experts

Description of the figure :
` C to` Tip of fishing rod DC
` AC to` stiring , `AF to` fly
Intially string was AC = `sqrt((180)^(2)+ (240)^(2))`
( by pythagores theorem)
` Rightarrow " " AC = sqrt(32400+57600)`
= 300 cm
BUT
When Nazima pulls in the string at the rate of 5cm/sec, she will pull ` 5xx 12 cm` in 12 sec. you can imagine that string will pull out 60 cm from C towards D. Now remaining string CA will become CG = 300-60=240 cm , because when string will pull in , its end point A as will as fly will move from A towards G. So, horizontal distance of fly at G ( now) from Nazima at E will be EG.
Now, ` GB^(2)= CG^(2)-CB^(2) ` ( by pythagoras theorem)
`= ( 240)^(2) - (280)^(2)= 57600-32400= 25200`
`GB = sqrt(25200) = 10sqrt(252)= 60sqrt7`
`= 60 xx 2.64575 = 158.745 cm `
Reqyuired distance = EG = GB + BE= 158.745 + 120
= 278.745 cm = 2.79 m ( approx).
Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    NAGEEN PRAKASHAN|Exercise Problems From NCERT/ Exemplar|14 Videos
  • TRIANGLES

    NAGEEN PRAKASHAN|Exercise Exercise 6a|23 Videos
  • STATISTICS

    NAGEEN PRAKASHAN|Exercise Revision Exercise Long Answer Questions|5 Videos
  • VOLUME AND SURFACE AREA OF SOLIDS

    NAGEEN PRAKASHAN|Exercise Revisions Exercise Long Answer Questions|5 Videos

Similar Questions

Explore conceptually related problems

Nazima is fly fishing in a stream. The tip of her fishing rod is 1.8 m above the surface of the water and the fly at the end of the string rests on the water 3.6 m away and 2.4 m from a point directly under the tip of the rod. Assuming that her string (form the tip of her rod to the fly) is taut, how much string does she have out (see figure)?

Nazima is fly fishing in a stream. The tip of her fishing rod is 1.8 m above the surface of the water and the fly at the end of the string rests on the water 3.6 m away and 2.4 m from a point directly under the tip of the rod. Assuming that her string (from the tip of her rod to the fly) is taut, how much string does she have out? If she pulls in the string at the rate of 5 cm per second, what will be the horizontal distance of the fly from her after 12 seconds?

A bird is flying 3m above the surface of water. To a fish underwater, the height of the bird from the water surface appears to be

An L-shaped tube with a small orifice is held in a water stream as shown in fig. The upper end of the tube is 10.6 cm above the surface of water. What will be the height of the jet of water coming from the orifice? Velocity of water stream is 2.45 m // s

An L-shaped tube with a small orifice is held in a water stream as shown in fig. the upper end of the tube is 10.6 cm above the surface of water. What will be the height of the jet of water coming from the orifice? (Velocity water steam is 2.45 m//s )

In a pond of water, a flame is held 2 m above the surface of the water. A fish is at depth of 4 m from the water surface. Refractive index of water is (4)/(3) . The apparent height of the flame from the eyes of fish is -

A bird is flying 3m above the surface of water,If the bird is diving vertically down with speed =6m//s his apparent velocity as seen by a stationary fish underwater is:

A fish lies at the bottom of a 4 m deep water lake. A bird flies 6m above the water surface and refractive index of water is 4//3 . Then the distance between

A man looks down on a fish of length 20 cm. His eye is 2m above the surface of the water (mu = 4//3) and the fish is 2m below the surface as shown in the figure the ratio of angular width Delta theta of the fish as seen by the man in presence of water to the Delta theta in the absence of water is (Delta theta is small)

One end of a light rod of length 1m is attached with a string of length 1m. Other end of the rod is attached at point O such that rod can move in a vertical circle. Other end of the string is attached with a block of mass 2kg. The minimum velocity that must be given to the block in horizontal direction so that it can complete the vertical is (g=10 m//s^(2))