`triangleABC and triangleDBC` are two triangles on the same base BC. A and D lies on opposite sides of BC. Prove that `(ar(triangleABC))/(ar(triangleDBC))= (AO)/(DO)`

In the adjoining figure, triangle ABC and triangleDBC are on the same base BC with A and D on opposite sides of BC such that ar(triangleABC)=ar(triangleDBC) . Show that BC bisect AD.

triangle ABC and triangle DBC are isosceles triangles on the same base BC. Prove that line AD bisects BC at right angles

In figure, ABC and ABD are two triangles on the same base AB. If line segment CD is bisected by AB at O , show that ar (triangleABC)=ar(triangleABD) .

ABC is a triangle in which D is the midpoint of BC and E is the midpoint of AD. Prove that ar(triangleBED)=(1)/(4)ar(triangleABC) .

In Fig. 6.44, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that (ar (ABC))/( ar (DBC))= (AO )/( DO )

In the same figure, Delta ABC and Delta DBC are on the same base BC . If AD is intersects BC at O, prove that (ar(Delta ABC))/(ar (Delta DBC))=(AO)/(DO)

In the given figure,Delta ABC and Delta DBC are on the same base BC.If AD intersects BC at O , prove that (ar(Delta ABC))/(ar(Delta DBC))=(AO)/(DO)

In the given figure, Delta ABC and Delta DBC have the same base BC. If AD and BC intersect at O, prove that (ar(DeltaABC))/(ar(Delta DBC))=(AO)/(DO)

ABC and DBC are two triangle on the same base BC such that A and D lie on the opposite sides of BC,AB=AC and DB =DC ,Show that AD is the perpedicular bisector of BC.

The vertex A of triangle ABC is joined to a point D on the side BC. The midpoint of AD is E. Prove that ar(triangleBEC)=(1)/(2)ar(triangleABC) .