6x^(2)+40=31x

Write the quotient and remainder when we divide : (6x^(2) - 31 x + 47) by (2x - 5)

Find the quotient and the remainder when 6x^(2)-31x+47 is divided by (2x-5)

Find the G.C.D of x^(3) - 10x^(2) + 31x - 30 and 2x^(3) - 8x^(2) + 2x + 12

The equation whose roots are reciprocals of the roots of 6x^(6) - 25x^(5) + 31x^(4) - 31x^(2) + 25x - 6 = 0 is

Find all the zeroes of x^(3)-10x^(2)+31x-30 if 2 is a zero of it.

If two roots are 9x^(3)-30x^(2)+31x-10=0 are in the ratio 2:5 then the roots are

Factorize : x^(3)+13x^(2)+31x-45 given that x+9 is a factor

If f(x)=sqrt(2x^(2)-6x+5)+sqrt(2x^(2)-40x+218) ,then the minimum value of f(x) is