[" 9.In a torch there are two cells each of "1.45" volt an "],[0.15Omega" .Each cell gives a current to filament of a lamp "],[" of "1.5Omega" ,then the value of current in ampere is - "]

In a torch there are two cells each of 1.45 volt and 0.15 Omega . Each cell gives a current to filament of a lamp of 1.5 Omega then the value of current in ampere is :–

In a torch there are two cells each of 1.45 volt and of internal resistance 0.15 Omega . Each cell gives a current to the filament of a lamp length of resistance 1.5 Omega , then the value of current in ampere is:-

The emf of a cell E is 15 V as shown in the figure with an internal resistance of 0.5Omega . Then the value of the current drawn from the cell is

The emf of a cell E is 15 V as shown in the figure with an internal resistance of 0.5Omega . Then the value of the current drawn from the cell is

A primary cell has an e.m.f. of 1.5 volt. When 5 Omega resistance is connected in the circuit, it gives a current of 0.2 ampere. The internal resistance of the cell is :

A primary cell has an e.m.f. 1.5 volt. When short circuited, it gives a current of 3 ampere. The internal resistance of the cell is

A primary cell has an e.m.f. of 1.5 volts, when short-circuited it gives a current of 3 amperes. The internal resistance of the cell is