`4a^2-16 a+16`

4a ^ (2) -16a + 16

Find the area of the region bounded by the circles x^2 + y^2 = 16 and (x+4)^2 +y^2 =16

Factorise the following expression - 4x^(2) + 16y^(2) + 16xy

Factories (i) 25 x ^(2) + 16 y ^(2) + 4z ^(2) - 40 xy + 16 yz - 20xz (ii) 9a ^(2) + 4b ^(2) + 16 c ^(2) + 12 ab - 16 bc - 24 ca

Factories (i) 25 x ^(2) + 16 y ^(2) + 4z ^(2) - 40 xy + 16 xy - 20xy (ii) 9a ^(2) + 4b ^(2) + 16 c ^(2) + 12 ab - 16 bc - 24 ca

Factories (i) 25 x ^(2) + 16 y ^(2) + 4z ^(2) - 40 xy + 16 yz - 20zx (ii) 9a ^(2) + 4b ^(2) + 16 c ^(2) + 12 ab - 16 bc - 24 ca

Factories (i) 25 x ^(2) + 16 y ^(2) + 4z ^(2) - 40 xy + 16 yz - 20zx (ii) 9a ^(2) + 4b ^(2) + 16 c ^(2) + 12 ab - 16 bc - 24 ca

Factorize: 16a^(2)-(25)/(4a^(2))( ii) 16a^(2)b-(b)/(16a^(2))100(x+y)^(2)-81(a+b)^(2)(x-1)^(2)-(x-2)^(2)

simplify (a - b)(a + b)(a^2 + b^2)(a^4 + b^4) (a^8 + b^8) (a^(16) + b^(16)) is: