" If "t_(n)=(1)/((n+1)!)," then "sum_(n=1)^(oo)t_(n)=

If t_(n) = 1/((n+1)!) , then sum_(n=1)^(infty) t_(n)=

If t_(n) = 1/((n+1)!) , then sum_(n=1)^(infty) t_(n)=

if in a series t_(n)=(n+1)/((n+2)!) then sum_(n=0)^(10)t_(n) equal to

sum_(n=1)^(oo) (2n)/(n!)=

If S_(n)=sum_(r=1)^(n)t_(r)=(1)/(6)n(2n^(2)+9n+13), then sum_(r=1)^(oo)(1)/(r*sqrt(t)) equals

Let T_(n) be the n^(th) term of a sequence for n=1,2,3,4... if 4T_(n+1)=T_(n) and T_(5)=(1)/(2560) then the value of sum_(n=1)^(oo)(T_(n)*T_(n+1)) is equal to