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An alpha-particle of energy 10 meV is sc...

An `alpha`-particle of energy 10 meV is scattered through `180^(@)` by a fixed uranium nucleus. The distance of the closest approach is of the order of

A

1Å

B

`10^(-10)` cm

C

`10^(-12)` cm

D

`10^(-15)` cm

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The correct Answer is:
C
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