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What is the diameter of H(2) atom?...

What is the diameter of `H_(2)` atom?

Text Solution

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Radius of the nth orbit
`r_(n)=(n^(2)h^(2)epsi_(0))/(pimZe^(2))`
`r_(1)=0.53Å`
`therefore` The diameter of `H_(2)=2xxr_(1)`
= `0.53xx2=1.06Å`
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