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The half-life of ""(38)^(90)Sr is 28 yea...

The half-life of `""_(38)^(90)Sr` is 28 years. What is the disintegration rate of 15 mg of this isotope?

Text Solution

Verified by Experts

`N=(6.023xx10^(23))/90xx15xx10^(-3)`
`(dN)/(dt)=lamdaN=(0.693)/T_(1//2)N`
= `0.693/(28xx365xx24xx60xx60)xx(6.023xx10^(23))/90xx15xx10^(-3)Bq`
= `7.878xx10^(10)Bq`.
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