Two cells each of 5V are connected in series across a `8 Omega` resistor and three parallel resistors of `4Omega, 6 Omega and 12 Omega`. Draw a circuit diagram for the above arrangement. Calculate (i) the current drawn fron the cell (ii) current through each resistor.

Explanation

Equivalent resistors of R. of 4, 6, 12 resistors connected in parallel is given by

`1/(R.)= 1/4 + 1/6+1/12`
Resistor of parallel combination R. `=2 Omega`
Total resistor i.e. `8 Omega` is connected in series with R..
`R_S = 8 + R.`
`R_S = 8 +2 = 10 Omega`
`:." "R_S = 10 Omega`
Net voltage (emf) = V = 10 V [ `because` cells are conneted in series total emf `epsi + epsi = 2 epsi`]
Circuit in through circuit `I = V/R` ( from ohm.s law)
`I = 10/10 = I = 1 A`
So the circuit through each cell and `8 Omega` resistor is 1A.