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An element X has the following isotopic ...

An element X has the following isotopic composition `.^200X =90%, .^199X=8%` and `.^202 X =2% `. The weighted average atomic mass of the element X is closest to

A

201u

B

202u

C

199u

D

200u

Text Solution

Verified by Experts

The correct Answer is:
B
`=((200xx90)+(199xx8)+(202xx2))/(100)`
`=199.96=200u`.
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