The mass of a gas that occupies a volume of 612.5 ml at room temperature and pressure `(25^@ c` and 1 atm pressure) is 1.1 g. The molar mass of the gas is

Options

A. `66.25 g mol^(-1)`
B. `44 g mol^(-1)`
C. `24.5g mol^(-1)`
D. `662.g mol^(-1)`

Answer

b

Explanation

`(612.5xx10^(-3)L)/(24.5Lmol^(-1))=-0.025` moles
Molar mass = `("mass")/("No.of.moles")`
`=(1.1g)/(0.025 "mol")=44 g "mol"^(-1)`