Calculate the empirical and molecular formula of a compound containing 76.6% carbon, 6.38 % hydrogen and rest oxygen its vapour density is 47

Explanation

Emprical formula `=C_(6)H_(6)O`
`n=("Molar mass")/("Calculate empirical formula mass")`
`= (2xx "vapour density")/(94) =(2xx47)/(94)=1`, since Molar mass `=2xx` Vapour density molecular formula `nxxn` empirical forumla
`therefore` Molecular formula `(C_6H_6O)xx1=C_6H_6O`.