Calculate the total number of electrons present in 17g of ammonia.

Explanation

No. of electrons present in one ammona `(NH)_3)`
molecule `(7+3)=10`
No. of moles of `NH_3=("Mass")/("Molar mass")=(17g)/(17g "mol"^(-1))=1` mol
No. of molecules present in 1 mol of `NH_(3) =10xx6.023xx10^23`
No. of electrons present in 1 mol of `NH_(3)=10xx6.023xx10^23 =6.023xx10^24`.